Call me an optimist, but I'm going to pick looking ahead over looking back.
As long as they win vs Red Deer they're guaranteed to be at least in the tiebreaker game. Even better than that, here's a scenario that I think could be seen as realistic:
London beats Rouyn Noranda
Brandon beats Red Deer
That would have standings at:
London: 3-0
Brandon: 1-2
Red Deer: 1-2
Rouyn Noranda: 1-2
From the Mem Cup website, the 3-way tiebreak procedure is:
"[i]2. (i) In the event three teams should tie for the final playoff place position, at the conclusion of the single round robin series of games, the game each team played against the first place team shall be removed from their records. The tie breaking formula shall be as follows: Add each team’s goals for with their goals against which sum you divide into such team’s goals for. The team with the highest percentage gains the higher position in the standings and an automatic berth as home team in the semi-final game. The remaining two teams shall play a sudden-death game with the winner to advance to the semi-final game. The home team in the sudden-death game will be the team that won the round robin game between the two teams.[/i]"
http://mastercardmemorialcup.ca/tiebreaker/
If I understand correctly that would mean that this loss tonight wouldnt count in the tiebreaker formula. That would mean that if Brandon were to beat Red Deer by the same 5-2 score as their last game and you do the math they would actually finish ahead of the other two teams, finish 2nd in round robin and have home ice in the semi-final against whoever wins a tiebreaker game between the other two teams.
A lot of "ifs" in there, but I don't think any of them are unrealistic if the WKs bring their A-game vs a Rebel team that will surely be motivated to knock Brandon out of the tournament less than a month after the Wheat Kings won the playoff series at the end of April.